2[6y+3]=3[2+4y]

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Solution for 2[6y+3]=3[2+4y] equation:


Simplifying
2[6y + 3] = 3[2 + 4y]

Reorder the terms:
2[3 + 6y] = 3[2 + 4y]
[3 * 2 + 6y * 2] = 3[2 + 4y]
[6 + 12y] = 3[2 + 4y]
6 + 12y = [2 * 3 + 4y * 3]
6 + 12y = [6 + 12y]

Add '-6' to each side of the equation.
6 + -6 + 12y = 6 + -6 + 12y

Combine like terms: 6 + -6 = 0
0 + 12y = 6 + -6 + 12y
12y = 6 + -6 + 12y

Combine like terms: 6 + -6 = 0
12y = 0 + 12y
12y = 12y

Add '-12y' to each side of the equation.
12y + -12y = 12y + -12y

Combine like terms: 12y + -12y = 0
0 = 12y + -12y

Combine like terms: 12y + -12y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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